(2x^2+x)=57

Solution for (2x^2+x)=57 equation:

(2x^2+x)=57

We move all terms to the left:

(2x^2+x)-(57)=0

We get rid of parentheses

2x^2+x-57=0

a = 2; b = 1; c = -57;
Δ = b2-4ac
Δ = 12-4·2·(-57)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{457}}{2*2}=\frac{-1-\sqrt{457}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{457}}{2*2}=\frac{-1+\sqrt{457}}{4}
$